The figure, not drawn to scale, O is the centre of the circle and AF // BE // CD. Find
- ∠ZOC
- ∠ZEO
(a)
∠FOB
= 180° - 94°
= 86° (Interior angles, AF//BO)
∠OCE = ∠OEC = 32° (Isosceles triangle)
∠BOC
= 32° + 32°
= 64° (Exterior angle of a triangle)
∠ZOC
= 86° + 64°
= 150°
(b)
∠EOC
= 180° - 32° -32°
= 116° (Isosceles triangle)
∠ZOE
= 360° - 150° - 116°
= 94° (Angles at a point)
ZO = OE = Radius
∠ZEO
= (180° - 94°) ÷ 2
= 86° ÷ 2
= 43° (Isosceles triangle)
Answer(s): (a) 150°; (b) 43°