The figure, not drawn to scale, O is the centre of the circle and XC // YB // ZA. Find
- ∠WOZ
- ∠WBO
(a)
∠COY
= 180° - 94°
= 86° (Interior angles, XC//YO)
∠OZB = ∠OBZ = 29° (Isosceles triangle)
∠YOZ
= 29° + 29°
= 58° (Exterior angle of a triangle)
∠WOZ
= 86° + 58°
= 144°
(b)
∠BOZ
= 180° - 29° -29°
= 122° (Isosceles triangle)
∠WOB
= 360° - 144° - 122°
= 94° (Angles at a point)
WO = OB = Radius
∠WBO
= (180° - 94°) ÷ 2
= 86° ÷ 2
= 43° (Isosceles triangle)
Answer(s): (a) 144°; (b) 43°