The figure, not drawn to scale, O is the centre of the circle and GM // HL // JK. Find
- ∠FOJ
- ∠FLO
(a)
∠MOH
= 180° - 94°
= 86° (Interior angles, GM//HO)
∠OJL = ∠OLJ = 30° (Isosceles triangle)
∠HOJ
= 30° + 30°
= 60° (Exterior angle of a triangle)
∠FOJ
= 86° + 60°
= 146°
(b)
∠LOJ
= 180° - 30° -30°
= 120° (Isosceles triangle)
∠FOL
= 360° - 146° - 120°
= 94° (Angles at a point)
FO = OL = Radius
∠FLO
= (180° - 94°) ÷ 2
= 86° ÷ 2
= 43° (Isosceles triangle)
Answer(s): (a) 146°; (b) 43°