The figure, not drawn to scale, O is the centre of the circle and RW // SV // TU. Find
- ∠QOT
- ∠QVO
(a)
∠WOS
= 180° - 94°
= 86° (Interior angles, RW//SO)
∠OTV = ∠OVT = 33° (Isosceles triangle)
∠SOT
= 33° + 33°
= 66° (Exterior angle of a triangle)
∠QOT
= 86° + 66°
= 152°
(b)
∠VOT
= 180° - 33° -33°
= 114° (Isosceles triangle)
∠QOV
= 360° - 152° - 114°
= 94° (Angles at a point)
QO = OV = Radius
∠QVO
= (180° - 94°) ÷ 2
= 86° ÷ 2
= 43° (Isosceles triangle)
Answer(s): (a) 152°; (b) 43°