The figure, not drawn to scale, O is the centre of the circle and HN // JM // KL. Find
- ∠GOK
- ∠GMO
(a)
∠NOJ
= 180° - 98°
= 82° (Interior angles, HN//JO)
∠OKM = ∠OMK = 28° (Isosceles triangle)
∠JOK
= 28° + 28°
= 56° (Exterior angle of a triangle)
∠GOK
= 82° + 56°
= 138°
(b)
∠MOK
= 180° - 28° -28°
= 124° (Isosceles triangle)
∠GOM
= 360° - 138° - 124°
= 98° (Angles at a point)
GO = OM = Radius
∠GMO
= (180° - 98°) ÷ 2
= 82° ÷ 2
= 41° (Isosceles triangle)
Answer(s): (a) 138°; (b) 41°