The figure, not drawn to scale, O is the centre of the circle and RW // SV // TU. Find
- ∠QOT
- ∠QVO
(a)
∠WOS
= 180° - 100°
= 80° (Interior angles, RW//SO)
∠OTV = ∠OVT = 34° (Isosceles triangle)
∠SOT
= 34° + 34°
= 68° (Exterior angle of a triangle)
∠QOT
= 80° + 68°
= 148°
(b)
∠VOT
= 180° - 34° -34°
= 112° (Isosceles triangle)
∠QOV
= 360° - 148° - 112°
= 100° (Angles at a point)
QO = OV = Radius
∠QVO
= (180° - 100°) ÷ 2
= 80° ÷ 2
= 40° (Isosceles triangle)
Answer(s): (a) 148°; (b) 40°