In the figure, O Is the centre of the circle and PU is parallel to RS. TV = TU, ∠ORP = 52° and ∠VUT = 49°. Find
- ∠SRX
- ∠RST
(a)
OP = OR = Radius
∠PRO = ∠RPO = 52° (Isosceles triangle, OPB)
∠ROX
= 52° + 52°
= 104° (Exterior angle of a triangle)
OR = OX = Radius
∠OXR
= (180° - 104°) ÷ 2
= 76° ÷ 2
= 38°
∠SRX = 38° (Alternate angles, RS//PE)
(b)
TV = TU
∠TUV = ∠TVU = 49° (Isosceles triangle TUF)
∠UTV
= 180° - 49° - 49°
= 82°
∠XTS = ∠UTV = 82° (Vertically opposite angles)
∠RST
= 180° - 82°
= 98° (Interior angles)
Answer(s): (a) 38°; (b) 98°