In the figure below, YZAB and ZAUT are squares. X and V are centres of square TUAZ and YZAB respectively. W is the centre of ZA. If YT = 28 cm, take π as
227 and find
- the perimeter of the shaded region,
- the area of the shaded region.
(a)
Circumference of big circle
=
227 x 14
= 44 cm
Circuference of four small semicircles
= 4 x
12 x
227 x 7
= 44 cm
Circumference of two quadrants
=
14 x 2 x
227 x 14
= 22 cm
Perimeter of the shaded region
= 44 + 44 + 22
= 110 cm
(b)
Area of big circle
=
227 x 7 x 7
= 154 cm
2Area of two shaded quadrant
=
12 x
227 x 7 x 7
= 77 cm
2 Area of shaded region
= 154 + 77
= 231 cm
2 Answer(s): (a) 110 cm; (b) 231 cm
2