In the figure below, UVWX and VWQP are squares. T and R are centres of square PQWV and UVWX respectively. S is the centre of VW. If UP = 84 cm, take π as
227 and find
- the perimeter of the shaded region,
- the area of the shaded region.
(a)
Circumference of big circle
=
227 x 42
= 132 cm
Circuference of four small semicircles
= 4 x
12 x
227 x 21
= 132 cm
Circumference of two quadrants
=
14 x 2 x
227 x 42
= 66 cm
Perimeter of the shaded region
= 132 + 132 + 66
= 330 cm
(b)
Area of big circle
=
227 x 21 x 21
= 1386 cm
2Area of two shaded quadrant
=
12 x
227 x 21 x 21
= 693 cm
2 Area of shaded region
= 1386 + 693
= 2079 cm
2 Answer(s): (a) 330 cm; (b) 2079 cm
2