In the figure below, EFGH and FGAZ are squares. D and B are centres of square ZAGF and EFGH respectively. C is the centre of FG. If EZ = 56 m, take π as
227 and find
- the perimeter of the shaded region,
- the area of the shaded region.
(a)
Circumference of big circle
=
227 x 28
= 88 m
Circuference of four small semicircles
= 4 x
12 x
227 x 14
= 88 m
Circumference of two quadrants
=
14 x 2 x
227 x 28
= 44 m
Perimeter of the shaded region
= 88 + 88 + 44
= 220 m
(b)
Area of big circle
=
227 x 14 x 14
= 616 m
2Area of two shaded quadrant
=
12 x
227 x 14 x 14
= 308 m
2 Area of shaded region
= 616 + 308
= 924 m
2 Answer(s): (a) 220 m; (b) 924 m
2