In the figure below, TUVW and UVPN are squares. S and Q are centres of square NPVU and TUVW respectively. R is the centre of UV. If TN = 28 m, take π as
227 and find
- the perimeter of the shaded region,
- the area of the shaded region.
(a)
Circumference of big circle
=
227 x 14
= 44 m
Circuference of four small semicircles
= 4 x
12 x
227 x 7
= 44 m
Circumference of two quadrants
=
14 x 2 x
227 x 14
= 22 m
Perimeter of the shaded region
= 44 + 44 + 22
= 110 m
(b)
Area of big circle
=
227 x 7 x 7
= 154 m
2Area of two shaded quadrant
=
12 x
227 x 7 x 7
= 77 m
2 Area of shaded region
= 154 + 77
= 231 m
2 Answer(s): (a) 110 m; (b) 231 m
2