The figure shows one big quadrant and two small semicircles. The radius of the big quadrant is 56 m.
- Find the perimeter of the shaded figure. (Take π = 3.14)
- Find the shaded area of this figure. (Take π = 3.14)
(a)
Circumference of the small circle
= 3.14 x 56
= 175.84 m
Diameter of the big quadrant
= 56 x 2
= 112 m
Circumference of the big quadrant
= 3.14 x 112 x
14= 87.92 m
Perimeter of the shaded figure
= 175.84 + 87.92
= 263.76 m
(b)
Area of the big quadrant
= 3.14 x 56 x 56 x
14 = 2461.76 m
2 Area of the triangle
=
12 x 56 x 56
= 1568 m
2 Area of shaded area
= 2461.76 - 1568
= 893.76 m
2 Answer(s): (a) 263.76 m; (b) 893.76 m
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