The figure shows one big quadrant and two small semicircles. The radius of the big quadrant is 32 m.
- Find the perimeter of the shaded figure. (Take π = 3.14)
- Find the shaded area of this figure. (Take π = 3.14)
(a)
Circumference of the small circle
= 3.14 x 32
= 100.48 m
Diameter of the big quadrant
= 32 x 2
= 64 m
Circumference of the big quadrant
= 3.14 x 64 x
14= 50.24 m
Perimeter of the shaded figure
= 100.48 + 50.24
= 150.72 m
(b)
Area of the big quadrant
= 3.14 x 32 x 32 x
14 = 803.84 m
2 Area of the triangle
=
12 x 32 x 32
= 512 m
2 Area of shaded area
= 803.84 - 512
= 291.84 m
2 Answer(s): (a) 150.72 m; (b) 291.84 m
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