The figure shows one big quadrant and two small semicircles. The radius of the big quadrant is 64 m.
- Find the perimeter of the shaded figure. (Take π = 3.14)
- Find the shaded area of this figure. (Take π = 3.14)
(a)
Circumference of the small circle
= 3.14 x 64
= 200.96 m
Diameter of the big quadrant
= 64 x 2
= 128 m
Circumference of the big quadrant
= 3.14 x 128 x
14= 100.48 m
Perimeter of the shaded figure
= 200.96 + 100.48
= 301.44 m
(b)
Area of the big quadrant
= 3.14 x 64 x 64 x
14 = 3215.36 m
2 Area of the triangle
=
12 x 64 x 64
= 2048 m
2 Area of shaded area
= 3215.36 - 2048
= 1167.36 m
2 Answer(s): (a) 301.44 m; (b) 1167.36 m
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