The figure shows one big quadrant and two small semicircles. The radius of the big quadrant is 46 m.
- Find the perimeter of the shaded figure. (Take π = 3.14)
- Find the shaded area of this figure. (Take π = 3.14)
(a)
Circumference of the small circle
= 3.14 x 46
= 144.44 m
Diameter of the big quadrant
= 46 x 2
= 92 m
Circumference of the big quadrant
= 3.14 x 92 x
14= 72.22 m
Perimeter of the shaded figure
= 144.44 + 72.22
= 216.66 m
(b)
Area of the big quadrant
= 3.14 x 46 x 46 x
14 = 1661.06 m
2 Area of the triangle
=
12 x 46 x 46
= 1058 m
2 Area of shaded area
= 1661.06 - 1058
= 603.06 m
2 Answer(s): (a) 216.66 m; (b) 603.06 m
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