The figure shows one big quadrant and two small semicircles. The radius of the big quadrant is 42 m.
- Find the perimeter of the shaded figure. (Take π = 3.14)
- Find the shaded area of this figure. (Take π = 3.14)
(a)
Circumference of the small circle
= 3.14 x 42
= 131.88 m
Diameter of the big quadrant
= 2 x 42
= 84 m
Circumference of the big quadrant
=
14 x 3.14 x 84
= 65.94 m
Perimeter of the shaded figure
= 131.88 + 65.94
= 197.82 m
(b)
Area of the big quadrant
=
14 x 3.14 x 42 x 42
= 1384.74 m
2 Area of the triangle
=
12 x 42 x 42
= 882 m
2 Shaded area
= 1384.74 - 882
= 502.74 m
2 Answer(s): (a) 197.82 m; (b) 502.74 m
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