The figure shows one big quadrant and two small semicircles. The radius of the big quadrant is 54 m.
- Find the perimeter of the shaded figure. (Take π = 3.14)
- Find the shaded area of this figure. (Take π = 3.14)
(a)
Circumference of the small circle
= 3.14 x 54
= 169.56 m
Diameter of the big quadrant
= 54 x 2
= 108 m
Circumference of the big quadrant
= 3.14 x 108 x
14= 84.78 m
Perimeter of the shaded figure
= 169.56 + 84.78
= 254.34 m
(b)
Area of the big quadrant
= 3.14 x 54 x 54 x
14 = 2289.06 m
2 Area of the triangle
=
12 x 54 x 54
= 1458 m
2 Area of shaded area
= 2289.06 - 1458
= 831.06 m
2 Answer(s): (a) 254.34 m; (b) 831.06 m
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