The figure shows one big quadrant and two small semicircles. The radius of the big quadrant is 52 m.
- Find the perimeter of the shaded figure. (Take π = 3.14)
- Find the shaded area of this figure. (Take π = 3.14)
(a)
Circumference of the small circle
= 3.14 x 52
= 163.28 m
Diameter of the big quadrant
= 52 x 2
= 104 m
Circumference of the big quadrant
= 3.14 x 104 x
14= 81.64 m
Perimeter of the shaded figure
= 163.28 + 81.64
= 244.92 m
(b)
Area of the big quadrant
= 3.14 x 52 x 52 x
14 = 2122.64 m
2 Area of the triangle
=
12 x 52 x 52
= 1352 m
2 Area of shaded area
= 2122.64 - 1352
= 770.64 m
2 Answer(s): (a) 244.92 m; (b) 770.64 m
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