The figure shows one big quadrant and two small semicircles. The radius of the big quadrant is 48 m.
- Find the perimeter of the shaded figure. (Take π = 3.14)
- Find the shaded area of this figure. (Take π = 3.14)
(a)
Circumference of the small circle
= 3.14 x 48
= 150.72 m
Diameter of the big quadrant
= 48 x 2
= 96 m
Circumference of the big quadrant
= 3.14 x 96 x
14= 75.36 m
Perimeter of the shaded figure
= 150.72 + 75.36
= 226.08 m
(b)
Area of the big quadrant
= 3.14 x 48 x 48 x
14 = 1808.64 m
2 Area of the triangle
=
12 x 48 x 48
= 1152 m
2 Area of shaded area
= 1808.64 - 1152
= 656.64 m
2 Answer(s): (a) 226.08 m; (b) 656.64 m
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