The figure is not drawn to scale. It is formed by quadrants and semicircles of two sizes. The radius of the larger quadrant is 5 m longer than the radius of the smaller quadrant. The radius of the smaller quadrant (Line F) is 14 m.
- Find the area of the shaded part.
- Find the perimeter of the dotted line. (Take π = 3.14)
(a)
Radius of the big semicircle above the dotted line
= 14 + 5
= 19 m
Area of the big semicircle above the dotted line
= 3.14 x 19 x 19 x
12 = 566.77 m
2 Area of the small semicircle above the dotted line
= Area of the big semicircle below the dotted line
= 3.14 x 14 x 14 x
12 = 307.72 m
2 Shaded area above the dotted line
= 566.77 - 307.72
= 259.05 m
2 Radius of the small semicircle below the dotted line
= 14 - 5
= 9 m
Area of the small semicircle below the dotted line
= 3.14 x 9 x 9 x 14
= 259.05 m
2 Shaded area below the dotted line
= 307.72 - 259.05
= 48.67 m
2 Total shaded area
= 259.05 + 48.67
= 307.72 m
2 (b)
14 x 4 = 56 m
Circumference of the curved lines
= 3.14 x 56
= 175.84 m
Perimeter of the shaded area
= 175.84 + (5 x 2)
= 175.84 + 10
= 185.84 m
Answer(s): (a) 307.72 m
2; (b) 185.84 m