The figure is not drawn to scale. It is formed by quadrants and semicircles of two sizes. The radius of the larger quadrant is 4 m longer than the radius of the smaller quadrant. The radius of the smaller quadrant (Line J) is 18 m.
- Find the area of the shaded part.
- Find the perimeter of the dotted line. (Take π = 3.14)
(a)
Radius of the big semicircle above the dotted line
= 18 + 4
= 22 m
Area of the big semicircle above the dotted line
= 3.14 x 22 x 22 x
12 = 759.88 m
2 Area of the small semicircle above the dotted line
= Area of the big semicircle below the dotted line
= 3.14 x 18 x 18 x
12 = 508.68 m
2 Shaded area above the dotted line
= 759.88 - 508.68
= 251.2 m
2 Radius of the small semicircle below the dotted line
= 18 - 4
= 14 m
Area of the small semicircle below the dotted line
= 3.14 x 14 x 14 x 18
= 251.2 m
2 Shaded area below the dotted line
= 508.68 - 251.2
= 257.48 m
2 Total shaded area
= 251.2 + 257.48
= 508.68 m
2 (b)
18 x 4 = 72 m
Circumference of the curved lines
= 3.14 x 72
= 226.08 m
Perimeter of the shaded area
= 226.08 + (4 x 2)
= 226.08 + 8
= 234.08 m
Answer(s): (a) 508.68 m
2; (b) 234.08 m