The figure is not drawn to scale. It is formed by quadrants and semicircles of two sizes. The radius of the larger quadrant is 3 cm longer than the radius of the smaller quadrant. The radius of the smaller quadrant (Line B) is 14 cm.
- Find the area of the shaded part.
- Find the perimeter of the dotted line. (Take π = 3.14)
(a)
Radius of the big semicircle above the dotted line
= 14 + 3
= 17 cm
Area of the big semicircle above the dotted line
= 3.14 x 17 x 17 x
12 = 453.73 cm
2 Area of the small semicircle above the dotted line
= Area of the big semicircle below the dotted line
= 3.14 x 14 x 14 x
12 = 307.72 cm
2 Shaded area above the dotted line
= 453.73 - 307.72
= 146.01 cm
2 Radius of the small semicircle below the dotted line
= 14 - 3
= 11 cm
Area of the small semicircle below the dotted line
= 3.14 x 11 x 11 x 14
= 146.01 cm
2 Shaded area below the dotted line
= 307.72 - 146.01
= 161.71 cm
2 Total shaded area
= 146.01 + 161.71
= 307.72 cm
2 (b)
14 x 4 = 56 cm
Circumference of the curved lines
= 3.14 x 56
= 175.84 cm
Perimeter of the shaded area
= 175.84 + (3 x 2)
= 175.84 + 6
= 181.84 cm
Answer(s): (a) 307.72 cm
2; (b) 181.84 cm