The figure is not drawn to scale. It is formed by quadrants and semicircles of two sizes. The radius of the larger quadrant is 9 cm longer than the radius of the smaller quadrant. The radius of the smaller quadrant (Line M) is 10 cm.
- Find the area of the shaded part.
- Find the perimeter of the dotted line. (Take π = 3.14)
(a)
Radius of the big semicircle above the dotted line
= 10 + 9
= 19 cm
Area of the big semicircle above the dotted line
= 3.14 x 19 x 19 x
12 = 566.77 cm
2 Area of the small semicircle above the dotted line
= Area of the big semicircle below the dotted line
= 3.14 x 10 x 10 x
12 = 157 cm
2 Shaded area above the dotted line
= 566.77 - 157
= 409.77 cm
2 Radius of the small semicircle below the dotted line
= 10 - 9
= 1 cm
Area of the small semicircle below the dotted line
= 3.14 x 1 x 1 x 10
= 409.77 cm
2 Shaded area below the dotted line
= 157 - 409.77
= -252.77 cm
2 Total shaded area
= 409.77 + -252.77
= 157 cm
2 (b)
10 x 4 = 40 cm
Circumference of the curved lines
= 3.14 x 40
= 125.6 cm
Perimeter of the shaded area
= 125.6 + (9 x 2)
= 125.6 + 18
= 143.6 cm
Answer(s): (a) 157 cm
2; (b) 143.6 cm