The figure is not drawn to scale. It is formed by quadrants and semicircles of two sizes. The radius of the larger quadrant is 3 m longer than the radius of the smaller quadrant. The radius of the smaller quadrant (Line G) is 34 m.
- Find the area of the shaded part.
- Find the perimeter of the dotted line. (Take π = 3.14)
(a)
Radius of the big semicircle above the dotted line
= 34 + 3
= 37 m
Area of the big semicircle above the dotted line
= 3.14 x 37 x 37 x
12 = 2149.33 m
2 Area of the small semicircle above the dotted line
= Area of the big semicircle below the dotted line
= 3.14 x 34 x 34 x
12 = 1814.92 m
2 Shaded area above the dotted line
= 2149.33 - 1814.92
= 334.41 m
2 Radius of the small semicircle below the dotted line
= 34 - 3
= 31 m
Area of the small semicircle below the dotted line
= 3.14 x 31 x 31 x 34
= 334.41 m
2 Shaded area below the dotted line
= 1814.92 - 334.41
= 1480.51 m
2 Total shaded area
= 334.41 + 1480.51
= 1814.92 m
2 (b)
34 x 4 = 136 m
Circumference of the curved lines
= 3.14 x 136
= 427.04 m
Perimeter of the shaded area
= 427.04 + (3 x 2)
= 427.04 + 6
= 433.04 m
Answer(s): (a) 1814.92 m
2; (b) 433.04 m