The figure is not drawn to scale. It is formed by quadrants and semicircles of two sizes. The radius of the larger quadrant is 3 m longer than the radius of the smaller quadrant. The radius of the smaller quadrant (Line F) is 24 m.
- Find the area of the shaded part.
- Find the perimeter of the dotted line. (Take π = 3.14)
(a)
Radius of the big semicircle above the dotted line
= 24 + 3
= 27 m
Area of the big semicircle above the dotted line
= 3.14 x 27 x 27 x
12 = 1144.53 m
2 Area of the small semicircle above the dotted line
= Area of the big semicircle below the dotted line
= 3.14 x 24 x 24 x
12 = 904.32 m
2 Shaded area above the dotted line
= 1144.53 - 904.32
= 240.21 m
2 Radius of the small semicircle below the dotted line
= 24 - 3
= 21 m
Area of the small semicircle below the dotted line
= 3.14 x 21 x 21 x 24
= 240.21 m
2 Shaded area below the dotted line
= 904.32 - 240.21
= 664.11 m
2 Total shaded area
= 240.21 + 664.11
= 904.32 m
2 (b)
24 x 4 = 96 m
Circumference of the curved lines
= 3.14 x 96
= 301.44 m
Perimeter of the shaded area
= 301.44 + (3 x 2)
= 301.44 + 6
= 307.44 m
Answer(s): (a) 904.32 m
2; (b) 307.44 m