Nora saved two coins every day from Monday to Sunday by putting them into a tin can. Each coin was either a 10¢ or 20¢ coin. The total value of the coins at the end of 6 weeks was $11.20. How many of the coins were 20¢ coins?
20¢ |
Value of 20¢ |
10¢ |
Value of 10¢ |
Total value |
84
|
84 x 20¢ = 1680¢ |
0 |
0 x 10¢ = 0 |
1680¢ |
83
|
83 x 20¢ = 1660¢ |
1 |
1 x 10¢ = 10¢ |
1670¢ |
28
|
28 x 20¢ = 560¢ |
56
|
56 x 10¢ = 560¢ |
1120¢ |
$1 = 100¢
$11.20 = 1120¢
Number of coins in one week
= 2 x 7
= 14
Number of coins in 6 weeks
= 6 x 14
= 84
Total amount saved if all the coins were 20¢
= 84 x 20
= 1680¢
Big difference between the total values of 20¢ coins and 10¢ coins
= 1680 - 1120
= 560¢
Small difference between the value of one 20¢ coin and one 10¢ coin
= 20 - 10
= 10¢
Number of 10¢ coins
= 560 ÷ 10
= 56
Number of 20¢ coins
= 84 - 56
= 28
Answer(s): 28