A box of croissants is shared among three children. Fabian gets 5 times as many croissants as Fred. Fred gets four times as many croissants as Peter. What fraction of the box of croissants does Fabian get?
| Fabian |
Fred |
Peter |
Total |
| 5x4 |
1x4 |
|
|
| |
4x1 |
1x1 |
|
| 20 u |
4 u |
1 u |
25 u |
The number of Fred's croissants is the repeated identity. Make the number of Fred's croissants the same. LCM of 1 and 4 is 4.
Total pieces of croissants
= 20 u + 4 u + 1 u
= 25 u
Fraction of the box of croissants that Fabian gets
=
2025 =
45 Answer(s):
45 
