Jenson is 40 years older than his niece. 10 years from now, his niece will be
12 of his age while his nephew will be
35 of his niece. Express his nephew’s present age as a fraction of Jenson's present age. Leave your answer in its simplest form.
|
Jenson |
Jenson's niece |
Jenson's nephew |
Difference between Jenson and Jenson's niece |
Before |
10 u - 10 |
5 u - 10 |
3 u - 10 |
40 |
Change |
+ 10 |
+ 10 |
+ 10 |
|
After
|
2x5 |
1x5 |
|
|
|
5x1 |
3x1 |
|
Comparing Jenson, his niece and his nephew in the end |
10 u |
5 u |
3 u |
5 u |
The repeated identity is the age of Jenson's niece. LCM of 1 and 5 is 5.
The difference in age between Jenson and Jenson's niece remains unchanged.
Difference in age between Jenson and Jenson's niece
= 10 u - 5 u
= 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
His nephew's present age
= 3 u - 10
= 3 x 8 - 10
= 24 - 10
= 14
Jenson's present age
= 10 u - 10
= 10 x 8 - 10
= 80 - 10
= 70
His nephew's present age as a fraction of Jenson's present age
=
1470=
15 Answer(s):
15