Luis is 20 years older than his daughter. 6 years from now, his daughter will be
12 of his age while his niece will be
35 of his daughter. Express his niece’s present age as a fraction of Luis's present age. Leave your answer in its simplest form.
|
Luis |
Luis's daughter |
Luis's niece |
Difference between Luis and Luis's daughter |
Before |
10 u - 6 |
5 u - 6 |
3 u - 6 |
20 |
Change |
+ 6 |
+ 6 |
+ 6 |
|
After
|
2x5 |
1x5 |
|
|
|
5x1 |
3x1 |
|
Comparing Luis, his daughter and his niece in the end |
10 u |
5 u |
3 u |
5 u |
The repeated identity is the age of Luis's daughter. LCM of 1 and 5 is 5.
The difference in age between Luis and Luis's daughter remains unchanged.
Difference in age between Luis and Luis's daughter
= 10 u - 5 u
= 5 u
5 u = 20
1 u = 20 ÷ 5 = 4
His niece's present age
= 3 u - 6
= 3 x 4 - 6
= 12 - 6
= 6
Luis's present age
= 10 u - 6
= 10 x 4 - 6
= 40 - 6
= 34
His niece's present age as a fraction of Luis's present age
=
634=
317 Answer(s):
317