Neave is 27 years older than his cousin. 4 years from now, his cousin will be
12 of his age while his child will be
13 of his cousin. Express his child’s present age as a fraction of Neave's present age. Leave your answer in its simplest form.
| |
Neave |
Neave's cousin |
Neave's child |
Difference between
Neave and Neave's cousin |
| Before |
6 u - 4 |
3 u - 4 |
1 u - 4 |
27 |
| Change |
+ 4 |
+ 4 |
+ 4 |
|
After
|
2x3 |
1x3 |
|
|
| |
3x1 |
1x1 |
|
Comparing Neave, his cousin and his child
in the end |
6 u |
3 u |
1 u |
3 u |
The repeated identity is the age of Neave's cousin. LCM of 1 and 3 is 3.
The difference in age between Neave and Neave's cousin remains unchanged.
Difference in age between Neave and Neave's cousin
= 6 u - 3 u
= 3 u
3 u = 27
1 u = 27 ÷ 3 = 9
His child's present age
= 1 u - 4
= 1 x 9 - 4
= 9 - 4
= 5
Neave's present age
= 6 u - 4
= 6 x 9 - 4
= 54 - 4
= 50
His child's present age as a fraction of Neave's present age
=
550=
110 Answer(s):
110 
