Paul is 24 years older than his daughter. 4 years from now, his daughter will be
12 of his age while his child will be
13 of his daughter. Express his child’s present age as a fraction of Paul's present age. Leave your answer in its simplest form.
| |
Paul |
Paul's daughter |
Paul's child |
Difference between
Paul and Paul's daughter |
| Before |
6 u - 4 |
3 u - 4 |
1 u - 4 |
24 |
| Change |
+ 4 |
+ 4 |
+ 4 |
|
After
|
2x3 |
1x3 |
|
|
| |
3x1 |
1x1 |
|
Comparing Paul, his daughter and his child
in the end |
6 u |
3 u |
1 u |
3 u |
The repeated identity is the age of Paul's daughter. LCM of 1 and 3 is 3.
The difference in age between Paul and Paul's daughter remains unchanged.
Difference in age between Paul and Paul's daughter
= 6 u - 3 u
= 3 u
3 u = 24
1 u = 24 ÷ 3 = 8
His child's present age
= 1 u - 4
= 1 x 8 - 4
= 8 - 4
= 4
Paul's present age
= 6 u - 4
= 6 x 8 - 4
= 48 - 4
= 44
His child's present age as a fraction of Paul's present age
=
444=
111 Answer(s):
111 
