David is 32 years older than his niece. 4 years from now, his niece will be
13 of his age while his daughter will be
12 of his niece. Express his daughter’s present age as a fraction of David's present age. Leave your answer in its simplest form.
|
David |
David's niece |
David's daughter |
Difference between David and David's niece |
Before |
6 u - 4 |
2 u - 4 |
1 u - 4 |
32 |
Change |
+ 4 |
+ 4 |
+ 4 |
|
After
|
3x2 |
1x2 |
|
|
|
2x1 |
1x1 |
|
Comparing David, his niece and his daughter in the end |
6 u |
2 u |
1 u |
4 u |
The repeated identity is the age of David's niece. LCM of 1 and 2 is 2.
The difference in age between David and David's niece remains unchanged.
Difference in age between David and David's niece
= 6 u - 2 u
= 4 u
4 u = 32
1 u = 32 ÷ 4 = 8
His daughter's present age
= 1 u - 4
= 1 x 8 - 4
= 8 - 4
= 4
David's present age
= 6 u - 4
= 6 x 8 - 4
= 48 - 4
= 44
His daughter's present age as a fraction of David's present age
=
444=
111 Answer(s):
111