Brandon is 40 years older than his son. 4 years from now, his son will be
12 of his age while his cousin will be
35 of his son. Express his cousin’s present age as a fraction of Brandon's present age. Leave your answer in its simplest form.
|
Brandon |
Brandon's son |
Brandon's cousin |
Difference between Brandon and Brandon's son |
Before |
10 u - 4 |
5 u - 4 |
3 u - 4 |
40 |
Change |
+ 4 |
+ 4 |
+ 4 |
|
After
|
2x5 |
1x5 |
|
|
|
5x1 |
3x1 |
|
Comparing Brandon, his son and his cousin in the end |
10 u |
5 u |
3 u |
5 u |
The repeated identity is the age of Brandon's son. LCM of 1 and 5 is 5.
The difference in age between Brandon and Brandon's son remains unchanged.
Difference in age between Brandon and Brandon's son
= 10 u - 5 u
= 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
His cousin's present age
= 3 u - 4
= 3 x 8 - 4
= 24 - 4
= 20
Brandon's present age
= 10 u - 4
= 10 x 8 - 4
= 80 - 4
= 76
His cousin's present age as a fraction of Brandon's present age
=
2076=
519 Answer(s):
519