Julian is 28 years older than his niece. 8 years from now, his niece will be
12 of his age while his child will be
37 of his niece. Express his child’s present age as a fraction of Julian's present age. Leave your answer in its simplest form.
|
Julian |
Julian's niece |
Julian's child |
Difference between Julian and Julian's niece |
Before |
14 u - 8 |
7 u - 8 |
3 u - 8 |
28 |
Change |
+ 8 |
+ 8 |
+ 8 |
|
After
|
2x7 |
1x7 |
|
|
|
7x1 |
3x1 |
|
Comparing Julian, his niece and his child in the end |
14 u |
7 u |
3 u |
7 u |
The repeated identity is the age of Julian's niece. LCM of 1 and 7 is 7.
The difference in age between Julian and Julian's niece remains unchanged.
Difference in age between Julian and Julian's niece
= 14 u - 7 u
= 7 u
7 u = 28
1 u = 28 ÷ 7 = 4
His child's present age
= 3 u - 8
= 3 x 4 - 8
= 12 - 8
= 4
Julian's present age
= 14 u - 8
= 14 x 4 - 8
= 56 - 8
= 48
His child's present age as a fraction of Julian's present age
=
448=
112 Answer(s):
112