Daniel is 20 years older than his daughter. 4 years from now, his daughter will be
12 of his age while his child will be
12 of his daughter. Express his child’s present age as a fraction of Daniel's present age. Leave your answer in its simplest form.
|
Daniel |
Daniel's daughter |
Daniel's child |
Difference between Daniel and Daniel's daughter |
Before |
4 u - 4 |
2 u - 4 |
1 u - 4 |
20 |
Change |
+ 4 |
+ 4 |
+ 4 |
|
After
|
2x2 |
1x2 |
|
|
|
2x1 |
1x1 |
|
Comparing Daniel, his daughter and his child in the end |
4 u |
2 u |
1 u |
2 u |
The repeated identity is the age of Daniel's daughter. LCM of 1 and 2 is 2.
The difference in age between Daniel and Daniel's daughter remains unchanged.
Difference in age between Daniel and Daniel's daughter
= 4 u - 2 u
= 2 u
2 u = 20
1 u = 20 ÷ 2 = 10
His child's present age
= 1 u - 4
= 1 x 10 - 4
= 10 - 4
= 6
Daniel's present age
= 4 u - 4
= 4 x 10 - 4
= 40 - 4
= 36
His child's present age as a fraction of Daniel's present age
=
636=
16 Answer(s):
16