Gabriel is 25 years older than his cousin. 5 years from now, his cousin will be ¹₂ of his age while his daughter will be ²₅ of his cousin. Express his daughter’s present age as a fraction of Gabriel's present age. Leave your answer in its simplest form.

	Gabriel	Gabriel's cousin	Gabriel's daughter	Difference between Gabriel and Gabriel's cousin
Before	10 u - 5	5 u - 5	2 u - 5	25
Change	+ 5	+ 5	+ 5
After	2x5	1x5
		5x1	2x1
Comparing Gabriel, his cousin and his daughter in the end	10 u	5 u	2 u	5 u

The repeated identity is the age of Gabriel's cousin. LCM of 1 and 5 is 5.

The difference in age between Gabriel and Gabriel's cousin remains unchanged.

Difference in age between Gabriel and Gabriel's cousin
= 10 u - 5 u 
= 5 u 

5 u = 25

1 u = 25 ÷ 5 = 5

His daughter's present age 
= 2 u - 5
= 2 x 5 - 5
= 10 - 5
= 5

Gabriel's present age
= 10 u - 5
= 10 x 5 - 5
= 50 - 5
= 45

His daughter's present age as a fraction of Gabriel's present age
= ⁵₄₅
= ¹₉

Answer(s): ¹₉