Linda spent
211 of her money on 9 croissants and 10 puffs. If each croissant costs twice as much as a puff, how many croissants could Linda buy with the rest of her money?
| |
Croissants |
Puffs |
| Number |
9 |
10 |
| Value |
2 u |
1 u |
| Total value |
18 u |
10 u |
Cost of 1 puff = 1 u
Cost of 1 croissant = 2 u
Total cost of 9 croissants and 10 puffs
= 9 x 2 u + 10 x 1 u
= 28 u
Fraction of Linda's money left
= 1 -
211 =
911211 of Linda's money = 28 u
111 of Linda's money = 28 u ÷ 2 = 14 u
911 of Linda's money = 14 u x 9 = 126 u
Number of croissants that Linda could buy
= 126 u ÷ 2 u
= 63
Answer(s): 63
