Kimberly spent
511 of her money on 6 macarons and 3 cupcakes. If each macaron costs twice as much as a cupcake, how many macarons could Kimberly buy with the rest of her money?
| |
Macarons |
Cupcakes |
| Number |
6 |
3 |
| Value |
2 u |
1 u |
| Total value |
12 u |
3 u |
Cost of 1 cupcake = 1 u
Cost of 1 macaron = 2 u
Total cost of 6 macarons and 3 cupcakes
= 6 x 2 u + 3 x 1 u
= 15 u
Fraction of Kimberly's money left
= 1 -
511 =
611511 of Kimberly's money = 15 u
111 of Kimberly's money = 15 u ÷ 5 = 3 u
611 of Kimberly's money = 3 u x 6 = 18 u
Number of macarons that Kimberly could buy
= 18 u ÷ 2 u
= 9
Answer(s): 9
