Fanny spent
211 of her money on 8 croissants and 4 cookies. If each croissant costs four times as much as a cookie, how many cookies could Fanny buy with the rest of her money?
| |
Croissants |
Cookies |
| Number |
8 |
4 |
| Value |
4 u |
1 u |
| Total value |
32 u |
4 u |
Cost of 1 cookie = 1 u
Cost of 1 croissant = 4 u
Total cost of 8 croissants and 4 cookies
= 8 x 4 u + 4 x 1 u
= 36 u
Fraction of Fanny's money left
= 1 -
211 =
911211 of Fanny's money = 36 u
111 of Fanny's money = 36 u ÷ 2 = 18 u
911 of Fanny's money = 18 u x 9 = 162 u
Number of cookies that Fanny could buy
= 162 u ÷ 1 u
= 162
Answer(s): 162
