Erika spent
712 of her money on 5 croissants and 6 biscuits. If each croissant costs thrice as much as a biscuit, how many biscuits could Erika buy with the rest of her money?
| |
Croissants |
Biscuits |
| Number |
5 |
6 |
| Value |
3 u |
1 u |
| Total value |
15 u |
6 u |
Cost of 1 biscuit = 1 u
Cost of 1 croissant = 3 u
Total cost of 5 croissants and 6 biscuits
= 5 x 3 u + 6 x 1 u
= 21 u
Fraction of Erika's money left
= 1 -
712 =
512712 of Erika's money = 21 u
112 of Erika's money = 21 u ÷ 7 = 3 u
512 of Erika's money = 3 u x 5 = 15 u
Number of biscuits that Erika could buy
= 15 u ÷ 1 u
= 15
Answer(s): 15
