Tiffany spent
35 of her money on 7 biscuits and 6 wafers. If each biscuit costs thrice as much as a wafer, how many biscuits could Tiffany buy with the rest of her money?
|
Biscuits |
Wafers |
Number |
7 |
6 |
Value |
3 u |
1 u |
Total value |
21 u |
6 u |
Cost of 1 wafer = 1 u
Cost of 1 biscuit = 3 u
Total cost of 7 biscuits and 6 wafers
= 7 x 3 u + 6 x 1 u
= 27 u
Fraction of Tiffany's money left
= 1 -
35 =
2535 of Tiffany's money = 27 u
15 of Tiffany's money = 27 u ÷ 3 = 9 u
25 of Tiffany's money = 9 u x 2 = 18 u
Number of biscuits that Tiffany could buy
= 18 u ÷ 3 u
= 6
Answer(s): 6