Elyse spent
211 of her money on 9 muffins and 10 cookies. If each muffin costs twice as much as a cookie, how many muffins could Elyse buy with the rest of her money?
|
Muffins |
Cookies |
Number |
9 |
10 |
Value |
2 u |
1 u |
Total value |
18 u |
10 u |
Cost of 1 cookie = 1 u
Cost of 1 muffin = 2 u
Total cost of 9 muffins and 10 cookies
= 9 x 2 u + 10 x 1 u
= 28 u
Fraction of Elyse's money left
= 1 -
211 =
911211 of Elyse's money = 28 u
111 of Elyse's money = 28 u ÷ 2 = 14 u
911 of Elyse's money = 14 u x 9 = 126 u
Number of muffins that Elyse could buy
= 126 u ÷ 2 u
= 63
Answer(s): 63