Abi spent
311 of her money on 4 wafers and 6 cookies. If each wafer costs thrice as much as a cookie, how many wafers could Abi buy with the rest of her money?
| |
Wafers |
Cookies |
| Number |
4 |
6 |
| Value |
3 u |
1 u |
| Total value |
12 u |
6 u |
Cost of 1 cookie = 1 u
Cost of 1 wafer = 3 u
Total cost of 4 wafers and 6 cookies
= 4 x 3 u + 6 x 1 u
= 18 u
Fraction of Abi's money left
= 1 -
311 =
811311 of Abi's money = 18 u
111 of Abi's money = 18 u ÷ 3 = 6 u
811 of Abi's money = 6 u x 8 = 48 u
Number of wafers that Abi could buy
= 48 u ÷ 3 u
= 16
Answer(s): 16
