Xylia spent
211 of her money on 5 shortbreads and 8 biscuits. If each shortbread costs twice as much as a biscuit, how many biscuits could Xylia buy with the rest of her money?
| |
Shortbreads |
Biscuits |
| Number |
5 |
8 |
| Value |
2 u |
1 u |
| Total value |
10 u |
8 u |
Cost of 1 biscuit = 1 u
Cost of 1 shortbread = 2 u
Total cost of 5 shortbreads and 8 biscuits
= 5 x 2 u + 8 x 1 u
= 18 u
Fraction of Xylia's money left
= 1 -
211 =
911211 of Xylia's money = 18 u
111 of Xylia's money = 18 u ÷ 2 = 9 u
911 of Xylia's money = 9 u x 9 = 81 u
Number of biscuits that Xylia could buy
= 81 u ÷ 1 u
= 81
Answer(s): 81
