Hilda spent
58 of her money on 8 wafers and 4 biscuits. If each wafer costs twice as much as a biscuit, how many wafers could Hilda buy with the rest of her money?
| |
Wafers |
Biscuits |
| Number |
8 |
4 |
| Value |
2 u |
1 u |
| Total value |
16 u |
4 u |
Cost of 1 biscuit = 1 u
Cost of 1 wafer = 2 u
Total cost of 8 wafers and 4 biscuits
= 8 x 2 u + 4 x 1 u
= 20 u
Fraction of Hilda's money left
= 1 -
58 =
3858 of Hilda's money = 20 u
18 of Hilda's money = 20 u ÷ 5 = 4 u
38 of Hilda's money = 4 u x 3 = 12 u
Number of wafers that Hilda could buy
= 12 u ÷ 2 u
= 6
Answer(s): 6
