Jaslyn spent
29 of her money on 3 wafers and 10 biscuits. If each wafer costs four times as much as a biscuit, how many biscuits could Jaslyn buy with the rest of her money?
| |
Wafers |
Biscuits |
| Number |
3 |
10 |
| Value |
4 u |
1 u |
| Total value |
12 u |
10 u |
Cost of 1 biscuit = 1 u
Cost of 1 wafer = 4 u
Total cost of 3 wafers and 10 biscuits
= 3 x 4 u + 10 x 1 u
= 22 u
Fraction of Jaslyn's money left
= 1 -
29 =
7929 of Jaslyn's money = 22 u
19 of Jaslyn's money = 22 u ÷ 2 = 11 u
79 of Jaslyn's money = 11 u x 7 = 77 u
Number of biscuits that Jaslyn could buy
= 77 u ÷ 1 u
= 77
Answer(s): 77
