Cathy spent
211 of her money on 4 biscuits and 10 wafers. If each biscuit costs thrice as much as a wafer, how many wafers could Cathy buy with the rest of her money?
| |
Biscuits |
Wafers |
| Number |
4 |
10 |
| Value |
3 u |
1 u |
| Total value |
12 u |
10 u |
Cost of 1 wafer = 1 u
Cost of 1 biscuit = 3 u
Total cost of 4 biscuits and 10 wafers
= 4 x 3 u + 10 x 1 u
= 22 u
Fraction of Cathy's money left
= 1 -
211 =
911211 of Cathy's money = 22 u
111 of Cathy's money = 22 u ÷ 2 = 11 u
911 of Cathy's money = 11 u x 9 = 99 u
Number of wafers that Cathy could buy
= 99 u ÷ 1 u
= 99
Answer(s): 99
