Marion spent
35 of her money on 9 wafers and 6 puffs. If each wafer costs twice as much as a puff, how many wafers could Marion buy with the rest of her money?
| |
Wafers |
Puffs |
| Number |
9 |
6 |
| Value |
2 u |
1 u |
| Total value |
18 u |
6 u |
Cost of 1 puff = 1 u
Cost of 1 wafer = 2 u
Total cost of 9 wafers and 6 puffs
= 9 x 2 u + 6 x 1 u
= 24 u
Fraction of Marion's money left
= 1 -
35 =
2535 of Marion's money = 24 u
15 of Marion's money = 24 u ÷ 3 = 8 u
25 of Marion's money = 8 u x 2 = 16 u
Number of wafers that Marion could buy
= 16 u ÷ 2 u
= 8
Answer(s): 8
