Dana spent
711 of her money on 8 cookies and 9 macarons. If each cookie costs five times as much as a macaron, how many macarons could Dana buy with the rest of her money?
| |
Cookies |
Macarons |
| Number |
8 |
9 |
| Value |
5 u |
1 u |
| Total value |
40 u |
9 u |
Cost of 1 macaron = 1 u
Cost of 1 cookie = 5 u
Total cost of 8 cookies and 9 macarons
= 8 x 5 u + 9 x 1 u
= 49 u
Fraction of Dana's money left
= 1 -
711 =
411711 of Dana's money = 49 u
111 of Dana's money = 49 u ÷ 7 = 7 u
411 of Dana's money = 7 u x 4 = 28 u
Number of macarons that Dana could buy
= 28 u ÷ 1 u
= 28
Answer(s): 28
