Emma spent
211 of her money on 6 croissants and 8 cookies. If each croissant costs twice as much as a cookie, how many croissants could Emma buy with the rest of her money?
| |
Croissants |
Cookies |
| Number |
6 |
8 |
| Value |
2 u |
1 u |
| Total value |
12 u |
8 u |
Cost of 1 cookie = 1 u
Cost of 1 croissant = 2 u
Total cost of 6 croissants and 8 cookies
= 6 x 2 u + 8 x 1 u
= 20 u
Fraction of Emma's money left
= 1 -
211 =
911211 of Emma's money = 20 u
111 of Emma's money = 20 u ÷ 2 = 10 u
911 of Emma's money = 10 u x 9 = 90 u
Number of croissants that Emma could buy
= 90 u ÷ 2 u
= 45
Answer(s): 45
